130=130-6t-16t^2

Solution for 130=130-6t-16t^2 equation:

130=130-6t-16t^2

We move all terms to the left:

130-(130-6t-16t^2)=0

We get rid of parentheses

16t^2+6t-130+130=0

We add all the numbers together, and all the variables

16t^2+6t=0

a = 16; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·16·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*16}=\frac{-12}{32}
=-3/8
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*16}=\frac{0}{32}
=0
$